For which set of data will the mean, the median and the mode all be equal?Group of answer choices1, 2, 5, 71, 1, 2, 51, 1, 21, 2, 5, 5, 8, 9

The mean, median, and mode will all be equal for the set of data 1, 1, 2, 5.

Here's why:

1. The mean is calculated by adding all the numbers in the set and dividing by the count of numbers. In this case, (1+1+2+5)/4 = 2.25.

2. The median is the middle number when the numbers are arranged in ascending order. If there is an even number of numbers, the median is the average of the two middle numbers. In this case, the numbers are already in order and there are 4 numbers, so the median is the average of the second and third numbers: (1+2)/2 = 1.5.

3. The mode is the number that appears most frequently. In this case, the number 1 appears twice, more than any other number, so the mode is 1.

So, the mean, median, and mode are not equal for this set of data.

Let's try the other sets:

1, 2, 5, 7: Mean = (1+2+5+7)/4 = 3.75 Median = (2+5)/2 = 3.5 Mode = none, because all numbers appear only once.

1, 1, 2, 2: Mean = (1+1+2+2)/4 = 1.5 Median = (1+2)/2 = 1.5 Mode = 1 and 2, because both numbers appear twice.

1, 2, 5, 5, 8, 9: Mean = (1+2+5+5+8+9)/6 = 5 Median = (5+5)/2 = 5 Mode = 5, because it appears twice, more than any other number.

So, the mean, median, and mode are all equal for the set of data 1, 2, 5, 5, 8, 9.