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If the area of a rectangular field is 21x2 – 7x and one of its sides is 7x, what is its other side?

Question

If the area of a rectangular field is 21x^2 - 7x and one of its sides is 7x, what is its other side?

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Solution

1. Break Down the Problem

We need to determine the unknown side of a rectangular field given its area and one known side.

Given:

  • Area = 21x27x 21x^2 - 7x
  • One side = 7x 7x

2. Relevant Concepts

The area A A of a rectangle can be expressed by the formula: A=length×width A = \text{length} \times \text{width} In this case, if one side is 7x 7x , the other side can be represented as: Other Side=AOne Side \text{Other Side} = \frac{A}{\text{One Side}} Thus: Other Side=21x27x7x \text{Other Side} = \frac{21x^2 - 7x}{7x}

3. Analysis and Detail

Let's perform the calculation: Other Side=21x27x7x \text{Other Side} = \frac{21x^2 - 7x}{7x} We can simplify this by dividing each term in the numerator by 7x 7x : =21x27x7x7x = \frac{21x^2}{7x} - \frac{7x}{7x} Calculating each term:

  1. 21x27x=3x \frac{21x^2}{7x} = 3x
  2. 7x7x=1 \frac{7x}{7x} = 1

Putting it together, we get: Other Side=3x1 \text{Other Side} = 3x - 1

4. Verify and Summarize

We have simplified the expression, and the calculations checked out.

Final Answer

The other side of the rectangular field is 3x1 3x - 1 .

This problem has been solved

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