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Let A and B be two disjoint events such that P(A) = 0.20 and P(B) = 0.60.What is P(A and B)? 0 0.12 0.68 0.80

Question

Let A and B be two disjoint events such that

  • P(A) = 0.20
  • P(B) = 0.60.

What is P(A and B)?

  • 0
  • 0.12
  • 0.68
  • 0.80
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Solution

1. Break Down the Problem

We need to find the probability of two disjoint events A and B occurring at the same time, denoted as P(A and B) P(A \text{ and } B) .

2. Relevant Concepts

For two disjoint (or mutually exclusive) events, the probability of both events occurring simultaneously is given by: P(A and B)=0 P(A \text{ and } B) = 0 This is because disjoint events cannot happen at the same time.

3. Analysis and Detail

Given that P(A)=0.20 P(A) = 0.20 and P(B)=0.60 P(B) = 0.60 , we can analyze the implications:

  • Since events A and B are disjoint, they do not overlap; hence the occurrence of one event completely excludes the possibility of the other occurring.

4. Verify and Summarize

Verifying our understanding of disjoint events, we confirm that: P(A and B)=0 P(A \text{ and } B) = 0

Final Answer

Thus, the probability P(A and B) P(A \text{ and } B) is 0 0 .

This problem has been solved

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