To balance the given redox reaction, we first need to balance the atoms other than H and O. Then, we balance the O atoms by adding H2O molecules. After that, we balance the H atoms by adding H+ ions. Finally, we balance the charge by adding electrons.

The balanced equation is:

2MnO4- + 10I- + 16H+ - 2MnO2 + 5I2 + 8H2O

From the balanced equation, we can see that there are no OH- ions in the products. Therefore, the value of z is 0.

Question

To balance the given redox reaction, we first need to balance the atoms other than H and O. Then, we balance the O atoms by adding H2O molecules. After that, we balance the H atoms by adding H+ ions. Finally, we balance the charge by adding electrons.

The balanced equation is:

2MnO4- + 10I- + 16H+ -> 2MnO2 + 5I2 + 8H2O

From the balanced equation, we can see that there are no OH- ions in the products. Therefore, the value of z is 0.

Knowee AI · Accepted Answer

To balance the given redox reaction, we first need to balance the atoms other than H and O. Then, we balance the O atoms by adding H2O molecules. After that, we balance the H atoms by adding H+ ions. Finally, we balance the charge by adding electrons.

The balanced equation is:

2MnO4- + 10I- + 16H+ -> 2MnO2 + 5I2 + 8H2O

From the balanced equation, we can see that there are no OH- ions in the products. Therefore, the value of z is 0.

2MnO−4+bI−+cH2O→xI2+yMnO2+zOH−If the above equation is balanced with integer coefficients, the value of z is

Question

2MnO−4 + bI− + cH2O → xI2 + yMnO2 + zOH−

Solution

Similar Questions

Upgrade your grade with Knowee