The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:1520 m22420 m22480 m22520 m2
Question
The difference between the length and breadth of a rectangle is 23 m. If its perimeter is 206 m, then its area is:
- 1520 m²
- 22420 m²
- 22480 m²
- 2520 m²
Solution
To find the area of the rectangle, we need to first determine the length and breadth of the rectangle.
Let's assume the length of the rectangle is L and the breadth is B.
According to the given information, the difference between the length and breadth is 23 m. So, we can write the equation as:
L - B = 23 ----(1)
The perimeter of a rectangle is given by the formula:
Perimeter = 2(L + B)
Substituting the given perimeter value of 206 m, we get:
2(L + B) = 206
Simplifying the equation, we have:
L + B = 103 ----(2)
Now, we have a system of equations (1) and (2) to solve.
To solve the system of equations, we can add equation (1) and equation (2):
(L - B) + (L + B) = 23 + 103
2L = 126
Dividing both sides by 2, we get:
L = 63
Substituting the value of L in equation (2), we can find B:
63 + B = 103
B = 103 - 63
B = 40
Now that we have the length (L = 63) and breadth (B = 40) of the rectangle, we can calculate the area using the formula:
Area = Length x Breadth
Area = 63 x 40
Area = 2520 m^2
Therefore, the area of the rectangle is 2520 m^2.
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