If the mean of the squares of first n natural numbers is 105, then the first n natural numbers i

It seems like your question got cut off. However, I can start answering based on what you've provided.

The formula for the mean of the squares of the first n natural numbers is (n(n + 1)(2n + 1))/6 divided by n. This is equal to (n + 1)(2n + 1)/6.

You've provided that this mean is 105. So, we have the equation:

(n + 1)(2n + 1)/6 = 105

Solving this equation will give us the value of n. However, since the question is incomplete, I'm not sure if there are additional steps or information to consider. Please provide the complete question.