Sum of pure and hybrid orbitals present in the hydrocarbon obtained by hydrolysis of Mg2C3 is ______

The hydrocarbon obtained by hydrolysis of Mg2C3 is propane (C3H8).

Step 1: Identify the number of atoms in the molecule. Propane has 3 Carbon atoms and 8 Hydrogen atoms.

Step 2: Determine the type of orbitals. Each Carbon atom in propane is sp3 hybridized. This means each Carbon atom has 4 hybrid orbitals. Since there are 3 Carbon atoms, there are a total of 12 hybrid orbitals.

Each Hydrogen atom has 1 pure s orbital. Since there are 8 Hydrogen atoms, there are a total of 8 pure orbitals.

Step 3: Add the number of pure and hybrid orbitals. The sum of pure and hybrid orbitals in propane is 12 (from Carbon) + 8 (from Hydrogen) = 20.

So, the sum of pure and hybrid orbitals present in the hydrocarbon obtained by hydrolysis of Mg2C3 is 20.