The 342nd term of the series 1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5, ……….. is
Question
Solution 1
The pattern of the series is such that each number n is repeated n times.
To find the 342nd term, we can use the formula for the sum of the first n natural numbers, which is n*(n+1)/2.
We need to find a number n such that n*(n+1)/2 is just less than or equal to 342.
If we try n=26, we get 26*( Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
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