An ore of iron has the formula Fe3O4. What is the approximate percentage of iron in this ore?A:72B:42C:52D:62
Question
An ore of iron has the formula Fe3O4. What is the approximate percentage of iron in this ore?
A: 72
B: 42
C: 52
D: 62
Solution
To calculate the percentage of iron in Fe3O4, we first need to find the molar mass of Fe3O4 and the molar mass of Fe.
Step 1: Calculate the molar mass of Fe3O4 The molar mass of Fe is approximately 55.845 g/mol and the molar mass of O is approximately 16.00 g/mol. So, the molar mass of Fe3O4 = (3 * 55.845 g/mol) + (4 * 16.00 g/mol) = 231.54 g/mol.
Step 2: Calculate the molar mass of Fe in Fe3O4 The molar mass of Fe in Fe3O4 = 3 * 55.845 g/mol = 167.535 g/mol.
Step 3: Calculate the percentage of Fe in Fe3O4 The percentage of Fe in Fe3O4 = (molar mass of Fe in Fe3O4 / molar mass of Fe3O4) * 100% = (167.535 g/mol / 231.54 g/mol) * 100% = 72.36%.
So, the approximate percentage of iron in Fe3O4 is 72%. Therefore, the answer is A:72.
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