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Determine the common difference, the fifth term, the nth term, and the 100th term of the arithmetic sequence.87, 2314, 157, 3714,   d= a5= an= a100=

Question

Determine the common difference, the fifth term, the nth term, and the 100th term of the arithmetic sequence.

Given the sequence: 87, 2314, 157, 3714
d= d =
a5= a_5 =
an= a_n =
a100= a_{100} =

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Solution

1. Break Down the Problem

To solve the problem, we need to:

  1. Determine the common difference dd of the arithmetic sequence.
  2. Find the fifth term a5a_5.
  3. Formulate the general term (nth term) ana_n.
  4. Calculate the 100th term a100a_{100}.

2. Relevant Concepts

In an arithmetic sequence:

  • The common difference dd is calculated as: d=anan1 d = a_{n} - a_{n-1}
  • The nth term can be expressed as: an=a1+(n1)d a_n = a_1 + (n-1)d
  • The fifth term can be calculated using the formula for the nth term.

3. Analysis and Detail

  1. First, we identify the first term a1=87a_1 = 87 and the second term a2=2314a_2 = 2314.
  2. Calculate the common difference dd: d=a2a1=231487=2227 d = a_2 - a_1 = 2314 - 87 = 2227
  3. Calculate the fifth term a5a_5: Using the formula for the nth term: a5=a1+(51)d=87+4×2227=87+8908=8995 a_5 = a_1 + (5-1)d = 87 + 4 \times 2227 = 87 + 8908 = 8995
  4. The general term ana_n is: an=87+(n1)×2227 a_n = 87 + (n-1) \times 2227
  5. Calculate the 100th term a100a_{100}: a100=87+(1001)×2227=87+99×2227=87+219273=219360 a_{100} = 87 + (100-1) \times 2227 = 87 + 99 \times 2227 = 87 + 219273 = 219360

4. Verify and Summarize

  • Common difference d=2227d = 2227
  • Fifth term a5=8995a_5 = 8995
  • General term an=87+(n1)×2227a_n = 87 + (n-1) \times 2227
  • The 100th term a100=219360a_{100} = 219360

Final Answer

  • d=2227d = 2227
  • a5=8995a_5 = 8995
  • an=87+(n1)×2227a_n = 87 + (n-1) \times 2227
  • a100=219360a_{100} = 219360

This problem has been solved

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