Namita is twice as old as Shreya. Five years ago her age was three times Shreya’s age. Find their present age
Question
Namita is twice as old as Shreya. Five years ago her age was three times Shreya’s age. Find their present age.
Solution
Let's denote Shreya's present age as 'x'.
According to the problem, Namita is twice as old as Shreya. So, Namita's present age is '2x'.
Five years ago, Shreya was 'x - 5' years old and Namita was '2x - 5' years old.
According to the problem, five years ago, Namita's age was three times Shreya's age. So, we can write the equation as '2x - 5 = 3(x - 5)'.
Solving this equation:
2x - 5 = 3x - 15
This simplifies to:
x = 10
So, Shreya is 10 years old.
And Namita, being twice as old as Shreya, is 20 years old.
So, Shreya's present age is 10 years and Namita's present age is 20 years.
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