Out of N, O, Ne, Na, Na+, select the species which have maximum and minimum ionization energy respectively.Na+, NaNe, NaNa+, ONe, N

To determine the species out of $\text{N}$, $\text{O}$, $\text{Ne}$, $\text{Na}$, and $\text{Na}^+$ that have the maximum and minimum ionization energy, we can rely on the periodic trends of ionization energy.

1. Break Down the Problem

We need to identify the elements and ions involved in the question:

• Neutral atoms: $\text{N}$, $\text{O}$, $\text{Ne}$, $\text{Na}$
• Charged ion: $\text{Na}^+$

2. Relevant Concepts

• Ionization Energy: The energy required to remove an electron from an atom or an ion in the gaseous state. It generally increases across a period and decreases down a group on the periodic table.
• Trends:
  • For metals like sodium (Na), the ionization energy is lower in comparison to nonmetals.
  • Noble gases like neon (Ne) usually have the highest ionization energies.

3. Analysis and Detail

• Ionization Energies of Given Species:
  • N (Nitrogen): Has a moderate ionization energy.
  • O (Oxygen): Has a higher ionization energy than nitrogen.
  • Ne (Neon): Has the highest ionization energy among these elements because it is a noble gas.
  • Na (Sodium): Has a low ionization energy due to its position as an alkali metal.
  • Na+ (Sodium Ion): The ion has lost an electron and thus has a higher ionization energy compared to its neutral atom, as removing an electron from a positively charged ion requires more energy.

4. Verify and Summarize

• Based on the trends and the properties of these elements:
  • Maximum Ionization Energy: $\text{Ne}$ (Neon)
  • Minimum Ionization Energy: $\text{Na}$ (Sodium)

Final Answer

• Maximum Ionization Energy: $\text{Ne}$ (Neon)
• Minimum Ionization Energy: $\text{Na}$ (Sodium)