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.A force of 1200 N acts on the surface of area 10 cm2 normally. What would be the thrust andpressure on the surface?

Question

.A force of 1200 N acts on the surface of area 10 cm² normally. What would be the thrust and pressure on the surface?

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Solution

The force acting on the surface is given as 1200 N and the area of the surface is given as 10 cm^2.

Step 1: Convert the area from cm^2 to m^2 because the standard unit of area in SI system is m^2. We know that 1 m^2 = 10,000 cm^2. So, 10 cm^2 = 10/10,000 = 0.001 m^2.

Step 2: Calculate the thrust. Thrust is the force applied on an object. In this case, the force applied on the surface is the thrust. So, the thrust on the surface is 1200 N.

Step 3: Calculate the pressure. Pressure is defined as the force applied per unit area. So, pressure = force / area = 1200 N / 0.001 m^2 = 1,200,000 Pa or 1.2 MPa.

So, the thrust on the surface is 1200 N and the pressure on the surface is 1.2 MPa.

This problem has been solved

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