The gas in a balloon occupies 3.50 L at 300 K. At which temperature will the balloon expand to 8.50 L?*1 point72.57 K7258.7 K728.57 K7.2557 K

This problem can be solved using the ideal gas law, which states that the volume of a gas is directly proportional to its temperature, assuming pressure and the amount of gas remain constant. This relationship can be expressed as V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Given: V1 = 3.50 L T1 = 300 K V2 = 8.50 L T2 = ?

We need to solve for T2.

Rearranging the formula to solve for T2 gives us T2 = (V2 * T1) / V1.

Substituting the given values into the formula gives us T2 = (8.50 L * 300 K) / 3.50 L.

Calculating this gives us T2 = 725.71 K.

So, the balloon will expand to 8.50 L at a temperature of 725.71 K. The closest answer to this is 725.8 K.