If OC + OA = 2OB, prove that A, B, and C are colinear and B is the midpoint of AC.
Question
If OC + OA = 2OB, prove that A, B, and C are colinear and B is the midpoint of AC.
Solution
Sure, here is the step by step proof:
-
Given that OC + OA = 2OB, we can rearrange this equation to OA + OC - 2OB = 0.
-
This can be further simplified to OA - OB + OC - OB = 0.
-
Now, we can rewrite this equation in terms of vectors: OA - OB = OB - OC.
-
This equation tells us that the vector from O to B is the same whether we go from O to A and then A to B, or from O to C and then C to B.
-
This implies that points A, B, and C are collinear, because the vectors along a straight line are proportional.
-
Furthermore, since OA - OB = OB - OC, it means that OB is the midpoint of AC.
Therefore, we have proved that A, B, and C are collinear and B is the midpoint of AC.
Similar Questions
ABCD is a parallelogram. Point P divides AB in theratio 2:3 and point Q divides DC in the ratio 4:1.Prove that OC is half of OA.
ABC is a right-angled triangle and O is the midpoint of the side opposite to the right angle.Explain why O is equidistant from A, B, and C.
If point ‘C’ lies between two points A and B such that AC = BC, thenAC = 1/4ABAC = 1/3ABAC = 3/4ABAC = 1/2AB
In the given figure A, B, C and D are collinear points. If AC = 3 cm, BD = 4 cm andBC = 2 cm, then AD is
In the adjoining gure, two points A and B lie on the same side of a line XY if AD XY, BEXY and Cis the midpoint of AB, prove that CD CE
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.