What will be the output of the following code? int i = 1;while(i<10){ if (i / 2 == 2) cout << i << “ ”;i++;}

Question

What will be the output of the following code?

int i = 1;
while(i&lt;10){  
    if (i / 2 == 2)  
        cout &lt;&lt; i &lt;&lt; &quot; &quot;;  
    i++;
}

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Solution

The output of the given code will be "4". Here's the step by step explanation:

The code starts with an integer i initialized to 1.
Then it enters a while loop which will continue to execute as long as i is less than 10.
Inside the loop, there's an if condition that checks if i divided by 2 equals 2. If it does, it prints the value of i followed by a space.
After the if condition, i is incremented by 1.
The loop then continues to the next iteration.

So, the only value of i for which i / 2 equals 2 is i = 4. Therefore, "4" will be printed.

This problem has been solved

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