An oven is turned on and used for 2700 seconds.During that time, it transfers 5.13MJ of energy.Calculate the power of this oven.

Sure, here are the steps to calculate the power of the oven:

1. First, we need to convert the energy from Megajoules (MJ) to Joules (J) because the standard unit of energy in physics is Joules. We know that 1 MJ = 1,000,000 J. So, 5.13 MJ = 5.13 * 1,000,000 = 5,130,000 J.

2. Next, we need to convert the time from seconds to hours because power is typically measured in Watts (Joules per second) or Kilowatts (Joules per hour). We know that 1 hour = 3600 seconds. So, 2700 seconds = 2700 / 3600 = 0.75 hours.

3. Now, we can calculate the power. Power (P) is defined as the amount of energy (E) transferred or converted per unit time (t). In mathematical form, P = E/t. Substituting the given values, P = 5,130,000 J / 0.75 hours = 6,840,000 J/hour.

4. Finally, we convert the power from Joules per hour to Kilowatts. We know that 1 Kilowatt = 1,000,000 Joules/hour. So, 6,840,000 J/hour = 6,840,000 / 1,000,000 = 6.84 KW.

So, the power of the oven is 6.84 KW.