Knowee
Questions
Features
Study Tools

In part (c) we found P(r ≥ 3) = 0.942. Use this value to calculate P(r ≤ 2).P(r ≤ 2)  =  1 − P(r ≥ 3) =  1 −

Question

In part (c) we found P(r≥3)=0.942 P(r \geq 3) = 0.942 . Use this value to calculate P(r≤2) P(r \leq 2) .

P(r≤2)=1−P(r≥3)=1− P(r \leq 2) \quad = \quad 1 - P(r \geq 3) \quad = \quad 1 -

🧐 Not the exact question you are looking for?Go ask a question

Solution

1. Break Down the Problem

We need to find P(r≤2) P(r \leq 2) using the value of P(r≥3) P(r \geq 3) that we found in part (c).

2. Relevant Concepts

The relationship between the probabilities is: P(r≤2)+P(r≥3)=1 P(r \leq 2) + P(r \geq 3) = 1

3. Analysis and Detail

Given: P(r≥3)=0.942 P(r \geq 3) = 0.942 We can use the concept above to find P(r≤2) P(r \leq 2) : P(r≤2)=1−P(r≥3) P(r \leq 2) = 1 - P(r \geq 3)

4. Verify and Summarize

Substituting the known value: P(r≤2)=1−0.942=0.058 P(r \leq 2) = 1 - 0.942 = 0.058

Final Answer

Thus, P(r≤2)=0.058 P(r \leq 2) = 0.058 .

This problem has been solved

Similar Questions

A discrete random variable X can only assume the values of 0, 1, 2 and 3.Given that 𝑃(𝑋 ≥ 2) = 0.6 , 𝑃(𝑋 ≤ 2) = 0.85Determine 𝑃(𝑋 = 2)

Suppose the cumulative distribution function of a random variable X is given by :Calculate P(1 < X < 3)?

Q and R are independent events. P(Q) = 0.4; P(Q AND R) = 0.16. Find P(R).P(R) =

Find the z value such that P(−z ≤ Z ≤ z) = 0.866.Multiple Choicez = 1.499z = −1.184z = 1.184z = −1.499

Given that z is a standard normal random variable, compute the following probabilities.P(z ≥ -1.44)Question 2Select one:a.0.7490b.0.9251c.0.0749d.0.5251

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.