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In part (c) we found P(r ≥ 3) = 0.942. Use this value to calculate P(r ≤ 2).P(r ≤ 2)  =  1 − P(r ≥ 3) =  1 −

Question

In part (c) we found P(r3)=0.942 P(r \geq 3) = 0.942 . Use this value to calculate P(r2) P(r \leq 2) .

P(r2)=1P(r3)=1 P(r \leq 2) \quad = \quad 1 - P(r \geq 3) \quad = \quad 1 -

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Solution

1. Break Down the Problem

We need to find P(r2) P(r \leq 2) using the value of P(r3) P(r \geq 3) that we found in part (c).

2. Relevant Concepts

The relationship between the probabilities is: P(r2)+P(r3)=1 P(r \leq 2) + P(r \geq 3) = 1

3. Analysis and Detail

Given: P(r3)=0.942 P(r \geq 3) = 0.942 We can use the concept above to find P(r2) P(r \leq 2) : P(r2)=1P(r3) P(r \leq 2) = 1 - P(r \geq 3)

4. Verify and Summarize

Substituting the known value: P(r2)=10.942=0.058 P(r \leq 2) = 1 - 0.942 = 0.058

Final Answer

Thus, P(r2)=0.058 P(r \leq 2) = 0.058 .

This problem has been solved

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