What is the order of the array np_c?np_a = np.array( [[1,2] , [3,4]])np_b = np.array( [[5,6] , [7,8]])np_c = np.hstack((np_a, np_b))print( np_c.shape )

The code you provided is written in Python, using the NumPy library for numerical operations. Here's a step-by-step explanation of what the code does:

1. np_a = np.array( [[1,2] , [3,4]]): This line creates a 2D NumPy array named np_a with two rows and two columns. The first row is [1, 2] and the second row is [3, 4].

2. np_b = np.array( [[5,6] , [7,8]]): This line creates another 2D NumPy array named np_b with two rows and two columns. The first row is [5, 6] and the second row is [7, 8].

3. np_c = np.hstack((np_a, np_b)): This line uses the hstack function from the NumPy library to horizontally stack the two arrays np_a and np_b. The result is a new 2D array np_c where the first row is [1, 2, 5, 6] and the second row is [3, 4, 7, 8].

4. print( np_c.shape ): This line prints the shape of the array np_c. The shape of a NumPy array is a tuple that indicates the size of each dimension. In this case, the shape of np_c is (2, 4), meaning it has two rows and four columns.