The Python code you provided is removing the first occurrence of the number 2 from the list and then summing up the remaining numbers in the list. Here's how it works:

1. The list is initially [1,3,5,2,4,6,2].
2. The `remove(2)` function removes the first occurrence of 2 from the list, so the list becomes [1,3,5,4,6,2].
3. The `sum(list1)` function adds up all the numbers in the list, so 1+3+5+4+6+2 equals 21.

So, the output of the Python code will be 21.

Question

The Python code you provided is removing the first occurrence of the number 2 from the list and then summing up the remaining numbers in the list. Here's how it works:

1. The list is initially [1,3,5,2,4,6,2].
2. The `remove(2)` function removes the first occurrence of 2 from the list, so the list becomes [1,3,5,4,6,2].
3. The `sum(list1)` function adds up all the numbers in the list, so 1+3+5+4+6+2 equals 21.

So, the output of the Python code will be 21.

Knowee AI · Accepted Answer

The Python code you provided is removing the first occurrence of the number 2 from the list and then summing up the remaining numbers in the list. Here's how it works:

1. The list is initially [1,3,5,2,4,6,2].
2. The `remove(2)` function removes the first occurrence of 2 from the list, so the list becomes [1,3,5,4,6,2].
3. The `sum(list1)` function adds up all the numbers in the list, so 1+3+5+4+6+2 equals 21.

So, the output of the Python code will be 21.

What will be the output of below Python code?list1=[1,3,5,2,4,6,2]list1.remove(2)print(sum(list1))18192122

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What will be the output of below Python code?

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