The output of the Python code will be:

For `s1.difference(s2)`, the output will be `{1, 2}`. This is because the `difference()` method returns a set that contains the difference between two sets. The difference between `s1` and `s2` is `{1, 2}` because these are the elements that exist in `s1` but not in `s2`.

For `s2.difference(s1)`, the output will be `{4, 5, 6}`. This is because the difference between `s2` and `s1` is `{4, 5, 6}` because these are the elements that exist in `s2` but not in `s1`.

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The output of the Python code will be:

For `s1.difference(s2)`, the output will be `{1, 2}`. This is because the `difference()` method returns a set that contains the difference between two sets. The difference between `s1` and `s2` is `{1, 2}` because these are the elements that exist in `s1` but not in `s2`.

For `s2.difference(s1)`, the output will be `{4, 5, 6}`. This is because the difference between `s2` and `s1` is `{4, 5, 6}` because these are the elements that exist in `s2` but not in `s1`.

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The output of the Python code will be:

For `s1.difference(s2)`, the output will be `{1, 2}`. This is because the `difference()` method returns a set that contains the difference between two sets. The difference between `s1` and `s2` is `{1, 2}` because these are the elements that exist in `s1` but not in `s2`.

For `s2.difference(s1)`, the output will be `{4, 5, 6}`. This is because the difference between `s2` and `s1` is `{4, 5, 6}` because these are the elements that exist in `s2` but not in `s1`.

What will be the output of the following Python code? s1={1, 2, 3} s2={3, 4, 5, 6} s1.difference(s2) s2.difference(s1)

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What will be the output of the following Python code?

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