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The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point(a) (2, 0)(b) (0, 2)(c) (3, 0)(d) (0, 3)

Question

The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point

(a) (2, 0)
(b) (0, 2)
(c) (3, 0)
(d) (0, 3)

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Solution

The graph of a linear equation cuts the y-axis at the point where x = 0.

So, to find the point where the graph of the equation 2x + 3y = 6 cuts the y-axis, we set x = 0 in the equation and solve for y.

Substituting x = 0 into the equation, we get:

2(0) + 3y = 6 0 + 3y = 6 3y = 6 y = 6 / 3 y = 2

So, the graph of the equation cuts the y-axis at the point (0, 2). Therefore, the correct answer is (b) (0, 2).

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