The graph of the linear equation 2x + 3y = 6 cuts the y-axis at the point(a) (2, 0)(b) (0, 2)(c) (3, 0)(d) (0, 3)
Question
Solution 1
The graph of a linear equation cuts the y-axis at the point where x = 0.
So, to find the point where the graph of the equation 2x + 3y = 6 cuts the y-axis, we set x = 0 in the equation and solve for y.
Substituting x = 0 into the equation, we get:
2(0) + 3y = 6 0 + 3y = 6 3y = 6 y = 6 / 3 y = 2
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