In common emitter BJT (npn) configuration if IB = 1mA , β = 100 . find emitter current
Question
In common emitter BJT (npn) configuration if
- IB = 1mA
- β = 100
find emitter current
Solution
In a common emitter BJT (npn) configuration, the emitter current (IE) is the sum of the base current (IB) and the collector current (IC).
The collector current (IC) can be calculated using the formula IC = β * IB, where β is the current gain.
Given that IB = 1mA and β = 100, we can calculate IC as follows:
IC = β * IB = 100 * 1mA = 100mA
Now, we can calculate the emitter current (IE) as follows:
IE = IB + IC = 1mA + 100mA = 101mA
So, the emitter current in this configuration is 101mA.
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