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What will be the output of the program?String s = "ABC"; s.toLowerCase(); s += "def"; System.out.println(s);ABCabcABCdefCompile Error

Question

What will be the output of the program?

String s = "ABC";
s.toLowerCase();
s += "def";
System.out.println(s);
  • ABC
  • abc
  • ABCdef
  • Compile Error
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Solution

The output of the program will be "ABCdef".

Here's the step by step explanation:

  1. The program starts by creating a String variable s and assigning it the value "ABC".

  2. The toLowerCase() method is called on s, which converts all the letters in the string to lower case. However, the result of this operation is not assigned to any variable, so it does not affect the original string s.

  3. The += operator is used to append "def" to the end of s. Now s is "ABCdef".

  4. Finally, s is printed to the console. So, the output of the program is "ABCdef".

This problem has been solved

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