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In a new system of units on mass, 5 kg is unit of mass, 5 m is unit of length and 1 sec. is unit of time. Find the value of 5N force in new system.

Question

In a new system of units on mass,

  • 5 kg is the unit of mass
  • 5 m is the unit of length
  • 1 sec. is the unit of time

Find the value of 5N force in new system.

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Solution

1. Break Down the Problem

To find the value of 5 N (Newtons) of force in the new system of units, we first need to understand the definition of force in terms of mass, length, and time in SI units: F=ma F = m \cdot a where F F is force in Newtons, m m is mass in kilograms, and a a is acceleration in meters per second squared.

2. Relevant Concepts

In SI units:

  • Force (N) is defined as 1N=1kgm/s2 1 \, \text{N} = 1 \, \text{kg} \cdot \text{m/s}^2 .

We need to convert mass (kg) and length (m) into the new system of units provided:

  • New unit of mass = 5 kg
  • New unit of length = 5 m

3. Analysis and Detail

First, we convert 5 N into our new system of units:

  1. In SI units, we have: 5N=5kgm/s2 5 \, \text{N} = 5 \, \text{kg} \cdot \text{m/s}^2

  2. Now, using the new units, we express mass and length:

    • 1 kg in new units = 15 \frac{1}{5} units of mass
    • 1 m in new units = 15 \frac{1}{5} units of length
  3. Substitute these into the equation: 5N=5(15units of mass15units of length/sec2) 5 \, \text{N} = 5 \cdot \left( \frac{1}{5} \, \text{units of mass} \cdot \frac{1}{5} \, \text{units of length}/\text{sec}^2 \right)

  4. Simplifying the right side: 5N=5(1515units of masslength/sec2) 5 \, \text{N} = 5 \cdot \left( \frac{1}{5} \cdot \frac{1}{5} \, \text{units of mass} \cdot \text{length}/\text{sec}^2 \right)

4. Verify and Summarize

  1. Calculate: =5125(units of mass) (length/s2)=525 (units of mass) (length/s2)=15(units of mass) (length/s2) = 5 \cdot \frac{1}{25} \, \text{(units of mass) (length/s}^2\text{)} = \frac{5}{25} \text{ (units of mass) (length/s}^2\text{)} = \frac{1}{5} \, \text{(units of mass) (length/s}^2\text{)}

Thus, the value of 5 N in the new system of units is expressed in terms of the new units of mass and length as 15(new unit of mass) (new unit of length/s2) \frac{1}{5} \, \text{(new unit of mass) (new unit of length/s}^2\text{)} .

Final Answer

The value of 5 N in the new system of units is 15(new unit of mass) (new unit of length/s2) \frac{1}{5} \, \text{(new unit of mass) (new unit of length/s}^2\text{)} .

This problem has been solved

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