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X observes a Weibull distribution with shape parameterβ = 5and characteristic lifeη = 45Find the mean of X (answers to 2 decimal places)

Question

X observes a Weibull distribution with shape parameter β=5 \beta = 5 and characteristic life η=45 \eta = 45 . Find the mean of X (answers to 2 decimal places).

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Solution

The mean of a Weibull distribution is given by the formula:

Mean = η * Γ(1 + 1/β)

where Γ is the gamma function, η is the scale parameter (characteristic life), and β is the shape parameter.

Given that η = 45 and β = 5, we can substitute these values into the formula:

Mean = 45 * Γ(1 + 1/5)

The gamma function Γ(1 + 1/5) can be calculated using a scientific calculator or a software package like R or Python. The value is approximately 1.03.

So, the mean of X is approximately:

Mean = 45 * 1.03 = 46.35

So, the mean of X is approximately 46.35 (rounded to two decimal places).

This problem has been solved

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