Find the equation of the line that passes through the point (−2,−3)(−2,−3), with gradient 2222​ . Give your answer in the form: 𝑎𝑥+𝑏𝑦+𝑐ax+by+c==00

The equation of a line in slope-intercept form is given by y = mx + c, where m is the slope (or gradient) and c is the y-intercept.

Given that the line passes through the point (-2,-3) and has a gradient of 2, we can substitute these values into the equation to find the y-intercept.

-3 = 2*(-2) + c -3 = -4 + c c = -3 + 4 c = 1

So, the equation of the line in slope-intercept form is y = 2x + 1.

To convert this to the form ax + by + c = 0, we can subtract y from both sides and then subtract 1 from both sides to get:

2x - y + 1 = 0

So, the equation of the line in the form ax + by + c = 0 is 2x - y + 1 = 0.