The provided SQL statement seems to be incorrect. Here's an explanation of the issues:

### Problem Breakdown
1. The SQL uses an aggregation function `count(film_id)` without a `GROUP BY` clause.
2. The condition `count(film_id) 20` is specified in the `WHERE` clause, which is not appropriate since aggregate functions are typically filtered using `HAVING`.

### Relevant Concepts
- In SQL, when you want to use aggregate functions like `COUNT` along with a condition, you must use `HAVING`.
- The `COUNT` function counts the number of rows that match a specified condition.

### Analysis and Detail
1. The query attempts to count the number of film IDs in the `film` table.
2. Without a proper structure, the query is invalid.

### Correct SQL Query
To check for films where the count exceeds 20, you may want to structure your query as follows:

```sql
SELECT COUNT(film_id)
FROM film
HAVING COUNT(film_id) 20;
```

### Verify and Summarize
- The original SQL query is invalid because it misuses the `COUNT` function and does not follow SQL syntax rules correctly.
- The correct approach uses `HAVING` to filter results after aggregation.

### Final Answer
The correct option is **b. Query is invalid**.

Question

The provided SQL statement seems to be incorrect. Here's an explanation of the issues:

### Problem Breakdown
1. The SQL uses an aggregation function `count(film_id)` without a `GROUP BY` clause.
2. The condition `count(film_id) > 20` is specified in the `WHERE` clause, which is not appropriate since aggregate functions are typically filtered using `HAVING`.

### Relevant Concepts
- In SQL, when you want to use aggregate functions like `COUNT` along with a condition, you must use `HAVING`.
- The `COUNT` function counts the number of rows that match a specified condition.

### Analysis and Detail
1. The query attempts to count the number of film IDs in the `film` table.
2. Without a proper structure, the query is invalid.

### Correct SQL Query
To check for films where the count exceeds 20, you may want to structure your query as follows:

```sql
SELECT COUNT(film_id)
FROM film
HAVING COUNT(film_id) > 20;
```

### Verify and Summarize
- The original SQL query is invalid because it misuses the `COUNT` function and does not follow SQL syntax rules correctly.
- The correct approach uses `HAVING` to filter results after aggregation.

### Final Answer
The correct option is **b. Query is invalid**.

Knowee AI · Accepted Answer