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If 56 g N2 and 64 g CH4 are mixed with 80 g SO3 gas, then mole fraction of CH4 is

Question

If 56 g N2 and 64 g CH4 are mixed with 80 g SO3 gas, then mole fraction of CH4 is

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Solution

To find the mole fraction of CH4, we first need to find the number of moles of each gas.

  1. The molar mass of N2 (Nitrogen) is approximately 28 g/mol, CH4 (Methane) is approximately 16 g/mol, and SO3 (Sulfur trioxide) is approximately 80 g/mol.

  2. Calculate the number of moles for each gas:

    • Moles of N2 = 56 g / 28 g/mol = 2 moles
    • Moles of CH4 = 64 g / 16 g/mol = 4 moles
    • Moles of SO3 = 80 g / 80 g/mol = 1 mole
  3. Calculate the total number of moles:

    • Total moles = Moles of N2 + Moles of CH4 + Moles of SO3
    • Total moles = 2 moles + 4 moles + 1 mole = 7 moles
  4. Calculate the mole fraction of CH4:

    • Mole fraction of CH4 = Moles of CH4 / Total moles
    • Mole fraction of CH4 = 4 moles / 7 moles = 0.57 (rounded to two decimal places)

So, the mole fraction of CH4 is 0.57.

This problem has been solved

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