A dc ammeter has an internal resistance of 0.1 ohm. A shunt of 1.010 x 10^-3 ohm is connected to the ammeter. What is the multiplier of the setup?
Question
Solution 1
The multiplier of the setup can be calculated using the formula for a shunt resistor in a DC ammeter, which is:
Multiplier = (Rm + Rs) / Rs
where: Rm = internal resistance of the ammeter Rs = resistance of the shunt
Given in the problem: Rm = 0.1 ohm Rs = 1.010 x 10^-3 ohm
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