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for a tree with dbh= 45.6cm, height= 27m and total stem volume of 1.78cum, the artificial form factor of the tree is:

Question

For a tree with the following characteristics:

  • DBH: 45.6 cm
  • Height: 27 m
  • Total Stem Volume: 1.78 cum

The artificial form factor of the tree is:

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Solution

The form factor of a tree is a dimensionless quantity that describes the shape of its stem. It is defined as the ratio of the actual stem volume to the volume of a cylinder with the same height and diameter at breast height (dbh).

The formula for the form factor (f) is:

f = V / (A * h)

where: V = stem volume A = cross-sectional area at breast height h = height of the tree

Given that the dbh = 45.6 cm, the radius (r) would be dbh/2 = 22.8 cm.

The cross-sectional area (A) can be calculated using the formula for the area of a circle, which is πr². So, A = π * (22.8 cm)² = 1633.5 cm².

However, since the volume is given in cubic meters (cum), we need to convert the area from cm² to m². We know that 1 m² = 10,000 cm², so A = 1633.5 cm² / 10,000 = 0.16335 m².

The height (h) is given as 27 m and the volume (V) is given as 1.78 cum.

Substituting these values into the formula for the form factor, we get:

f = 1.78 cum / (0.16335 m² * 27 m) = 0.403

So, the artificial form factor of the tree is approximately 0.403.

This problem has been solved

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