The wavelength of the first overtone of a note in a closed pipe of length 33 cm is?

Sure, here's how to calculate the wavelength of the first overtone in a closed pipe:

1. First, it's important to understand that in a closed pipe, the first overtone is the third harmonic. This means that the pipe length is 1/4 of the wavelength of the fundamental frequency, and 3/4 of the wavelength of the first overtone.

2. Given that the length of the pipe is 33 cm, we can set up the following equation to solve for the wavelength (λ) of the first overtone:

   L = 3/4 λ

3. Plugging in the given length (L) into the equation gives us:

   33 cm = 3/4 λ

4. To solve for λ, we can multiply both sides of the equation by 4/3:

   λ = (4/3) * 33 cm

5. This gives us λ = 44 cm.

So, the wavelength of the first overtone of a note in a closed pipe of length 33 cm is 44 cm.