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Find the mass and weight of the air at 20C in a living room with a 4.0m*5.0m floor and a ceiling3.0 high, and the mass and weight of an equal volume of water.

Question

Find the mass and weight of the air at 20C in a living room with a 4.0m*5.0m floor and a ceiling 3.0 high, and the mass and weight of an equal volume of water.

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Solution

Sure, let's break this down step by step.

First, we need to find the volume of the room. The volume of a rectangular prism (which this room is) is found by multiplying the length, width, and height.

Volume = length * width * height Volume = 4.0m * 5.0m * 3.0m = 60.0 cubic meters

Next, we need to find the mass of the air in the room. The density of air at 20C is approximately 1.204 kg/m^3. We find mass by multiplying volume by density.

Mass (air) = Volume * Density Mass (air) = 60.0 m^3 * 1.204 kg/m^3 = 72.24 kg

The weight of an object is its mass times the acceleration due to gravity. On Earth, this is approximately 9.8 m/s^2.

Weight (air) = Mass * gravity Weight (air) = 72.24 kg * 9.8 m/s^2 = 708 kg*m/s^2 or 708 Newtons

Now, let's find the mass and weight of an equal volume of water. The density of water is approximately 1000 kg/m^3.

Mass (water) = Volume * Density Mass (water) = 60.0 m^3 * 1000 kg/m^3 = 60000 kg

Weight (water) = Mass * gravity Weight (water) = 60000 kg * 9.8 m/s^2 = 588000 kg*m/s^2 or 588000 Newtons

So, the mass of the air in the room is 72.24 kg and its weight is 708 Newtons. The mass of an equal volume of water is 60000 kg and its weight is 588000 Newtons.

This problem has been solved

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