Using the discriminant, determine the number of solutions for the quadratic equation 2x2+5x+1=02𝑥2+5𝑥+1=0.Δ=Δ= ∴∴ there is/are solution(s)

Question

Using the discriminant, determine the number of solutions for the quadratic equation

$2x^2 + 5x + 1 = 0$

$\Delta =$

$\therefore \text{there is/are } \text{solution(s)}$

🧐 Not the exact question you are looking for?Go ask a question

Solution

The discriminant of a quadratic equation is given by the formula Δ = b² - 4ac, where a, b, and c are the coefficients of the quadratic equation ax² + bx + c = 0.

In the given equation 2x² + 5x + 1 = 0, a = 2, b = 5, and c = 1.

Substituting these values into the formula, we get:

Δ = (5)² - 4*(2)*(1) Δ = 25 - 8 Δ = 17

Since the discriminant is greater than 0, the quadratic equation has two distinct real solutions.

This problem has been solved

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.

Using the discriminant, determine the number of solutions for the quadratic equation 2x2+5x+1=02𝑥2+5𝑥+1=0.Δ=Δ= ∴∴ there is/are solution(s)

Question