A park, in the shape of a quadrilateral ABCD, has ∠c = 90଴, AB=9m, BC=12m, CD=5mand AD=8m. How much area does it occupy?

The park is in the shape of a quadrilateral with one angle being 90 degrees. This suggests that the park is in the shape of two right-angled triangles (Triangle ABC and Triangle ACD).

1. First, let's find the area of Triangle ABC. Since it's a right-angled triangle, we can use the formula for the area of a right-angled triangle, which is 1/2 * base * height. Here, AB is the base and BC is the height. So, the area of Triangle ABC = 1/2 * AB * BC = 1/2 * 9m * 12m = 54 square meters.

2. Next, let's find the area of Triangle ACD. Again, since it's a right-angled triangle, we can use the formula for the area of a right-angled triangle, which is 1/2 * base * height. Here, AD is the base and CD is the height. So, the area of Triangle ACD = 1/2 * AD * CD = 1/2 * 8m * 5m = 20 square meters.

3. Finally, to find the total area of the park, we add the areas of Triangle ABC and Triangle ACD together. So, the total area of the park = area of Triangle ABC + area of Triangle ACD = 54 square meters + 20 square meters = 74 square meters.

So, the park occupies an area of 74 square meters.