Suatu rangkaian resistor paralel dengan resitor pertama bernilai 6 ohm dan yang kedua bernilai 3 ohm. Hambatan total nya adalah . . . ΩΩQuestion 3Answer62354

1. Break Down the Problem

We need to calculate the total resistance of a parallel circuit consisting of two resistors, one with a resistance of 6 ohms and the other with a resistance of 3 ohms.

2. Relevant Concepts

For resistors in parallel, the formula for calculating the total resistance $R_t$ is given by:

$\frac{1}{R_t} = \frac{1}{R_1} + \frac{1}{R_2}$

Where:

• $R_1 = 6 \, \Omega$
• $R_2 = 3 \, \Omega$

3. Analysis and Detail

Using the formula, we can substitute the values of $R_1$ and $R_2$:

$\frac{1}{R_t} = \frac{1}{6} + \frac{1}{3}$

To add these fractions, find a common denominator, which is 6:

$\frac{1}{R_t} = \frac{1}{6} + \frac{2}{6} = \frac{3}{6}$

Now, simplify $\frac{3}{6}$:

$\frac{1}{R_t} = \frac{1}{2}$

To find $R_t$, we take the reciprocal:

$R_t = 2 \, \Omega$

4. Verify and Summarize

The calculations show that the total resistance of the circuit is indeed valid as per the formula for resistors in parallel.

Final Answer

The total resistance $R_t$ is $2 \, \Omega$.