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At what time between 4 and 5 o'clock will the hands of a watch point in opposite directions?

Question

At what time between 4 and 5 o'clock will the hands of a watch point in opposite directions?

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Solution

1. Break Down the Problem

We need to determine the time between 4 and 5 o'clock when the minute and hour hands of a clock are pointing in opposite directions (180 degrees apart).

2. Relevant Concepts

To find the positions of the clock hands:

  • The hour hand moves at a rate of 30 30 degrees per hour (since 360 360 degrees / 12 12 hours = 30 30 degrees per hour).
  • The minute hand moves at 6 6 degrees per minute (since 360 360 degrees / 60 60 minutes = 6 6 degrees per minute).

3. Analysis and Detail

At 4:00, the hour hand is at: Position of hour hand=4×30=120 degrees \text{Position of hour hand} = 4 \times 30 = 120 \text{ degrees} Let m m be the number of minutes past 4 o'clock.

Position of the hour hand at 4:m 4:m : Position of hour hand at 4:m=120+m2 degrees \text{Position of hour hand at } 4:m = 120 + \frac{m}{2} \text{ degrees} (since 30 30 degrees per hour = 12 \frac{1}{2} degrees per minute)

Position of the minute hand at 4:m 4:m : Position of minute hand at 4:m=6m degrees \text{Position of minute hand at } 4:m = 6m \text{ degrees}

To find when the hands are opposite, we set up the equation: (120+m2)6m=180 \left| \left(120 + \frac{m}{2}\right) - 6m \right| = 180

This creates two cases to solve:

  1. 120+m26m=180 120 + \frac{m}{2} - 6m = 180
  2. 6m(120+m2)=180 6m - \left(120 + \frac{m}{2}\right) = 180

Solving Case 1:

120+m26m=180 120 + \frac{m}{2} - 6m = 180 m26m=180120 \frac{m}{2} - 6m = 180 - 120 m26m=60 \frac{m}{2} - 6m = 60 Multiplying through by 2 to eliminate the fraction: m12m=12011m=120m=12011 (not valid) m - 12m = 120 \Rightarrow -11m = 120 \Rightarrow m = -\frac{120}{11} \text{ (not valid)}

Solving Case 2:

6m(120+m2)=180 6m - \left(120 + \frac{m}{2}\right) = 180 6m120m2=180 6m - 120 - \frac{m}{2} = 180 Combining like terms: 6mm2=30012mm2=30011m2=300 6m - \frac{m}{2} = 300 \Rightarrow \frac{12m - m}{2} = 300 \Rightarrow \frac{11m}{2} = 300 Multiplying through by 2 2 : 11m=600m=6001154.55 minutes 11m = 600 \Rightarrow m = \frac{600}{11} \approx 54.55 \text{ minutes}

4. Verify and Summarize

The approximate solution is 54.55 54.55 minutes past 4. This corresponds to about 4:55 4:55 and 511 \frac{5}{11} seconds.

Final Answer

The hands of the clock will point in opposite directions at approximately 4:54 and 5/11 minutes (or about 4:54:32).

This problem has been solved

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