Consider the equation of parabola y=5x2−30x+45y=5x 2 −30x+45.Its vertex is located at (( ,, ))
Question
Solution 1
The vertex of a parabola given in the form y = ax^2 + bx + c is at the point (h, k), where h = -b/2a and k is the value of y at h.
Given the equation of the parabola y = 5x^2 - 30x + 45, the coefficients are a = 5, b = -30, and c = 45.
Step 1: Calculate h h = -b/2a = -(-30)/(2*5) = 30/10 = 3
Step Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI is a powerful AI-powered study tool designed to help you to solve study problem.
Knowee AI
Similar Questions
Consider the equation of parabola y=5x2−30x+45y=5x 2 −30x+45.Its vertex is located at (( ,, ))
The vertex form of the equation of a parabola is y = 3(x - 4)2 - 22.What is the standard form of the equation?
The equation of the circle drawn with the focus of the parabola (x – 1 )2 – 8y = 0 as its centre and touching the parabola at its vertex is :
What are the x-intercepts and the vertex of the parabola represented by y = 2x2 - 5x -12?
orWatch a videoWrite the equation in vertex form for the parabola with focus (0,9) and directrix y=–3.Simplify any fractions.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.