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Differentiate the function y = tan(5x-4)Question 10Select one:5 sec^2 (5x-4)2x+13y20(4𝑥-3)415(3x+2)

Question

Differentiate the function

y=tan(5x4) y = \tan(5x-4)

Question 10

Select one:

  • 5 sec²(5x-4)
  • 2x + 13y
  • 20(4𝑥-3)
  • 415(3x+2)
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Solution

Break Down the Problem

  1. Identify the function to differentiate: y=tan(5x4) y = \tan(5x - 4) .
  2. Recognize the need to apply the chain rule for differentiation since the function is a composite function.

Relevant Concepts

  1. The derivative of tan(u) \tan(u) with respect to u u is sec2(u) \sec^2(u) .
  2. Apply the chain rule: If y=tan(u) y = \tan(u) , then dydx=sec2(u)dudx \frac{dy}{dx} = \sec^2(u) \cdot \frac{du}{dx} , where u=5x4 u = 5x - 4 .

Analysis and Detail

  1. Compute dudx \frac{du}{dx} : u=5x4    dudx=5 u = 5x - 4 \implies \frac{du}{dx} = 5
  2. Now, substitute back into the derivative: dydx=sec2(5x4)5 \frac{dy}{dx} = \sec^2(5x - 4) \cdot 5

Verify and Summarize

  1. Thus, the derivative is: dydx=5sec2(5x4) \frac{dy}{dx} = 5 \sec^2(5x - 4)

Final Answer

The correct answer is 5sec2(5x4) 5 \sec^2(5x - 4) .

This problem has been solved

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