If Ne has an effusion rate of 9.42 moles/sec. What would the effusion rate for CO be in moles/sec? Round to 2 decimal places.

To solve this problem, we need to use Graham's law of effusion. This law states that the rate of effusion of a gas is inversely proportional to the square root of its molar mass.

The formula for Graham's law of effusion is:

Rate1/Rate2 = sqrt(M2/M1)

Where:

• Rate1 and Rate2 are the rates of effusion of the two gases.
• M1 and M2 are the molar masses of the two gases.

Given in the problem:

• The rate of effusion of Ne (Rate1) is 9.42 moles/sec.
• The molar mass of Ne (M1) is approximately 20.18 g/mol.
• The molar mass of CO (M2) is approximately 28.01 g/mol.

We need to find the rate of effusion for CO (Rate2).

Plugging the given values into the formula, we get:

9.42/Rate2 = sqrt(28.01/20.18)

Solving for Rate2, we get:

Rate2 = 9.42 / sqrt(28.01/20.18)

Calculating the above expression gives us the rate of effusion for CO, which is approximately 7.97 moles/sec when rounded to two decimal places.