For P(A or B), "or" is inclusive, it it includes the possibility that both event A and event B happen.

Your statement about the probability $P(A \text{ or } B)$ being inclusive is correct. In probability theory, the "or" in this context refers to the occurrence of either event A, event B, or both events occurring simultaneously.

The formula to calculate the probability of the union of two events A and B can be expressed as:

$P(A \cup B) = P(A) + P(B) - P(A \cap B)$

Where:

• $P(A)$ is the probability of event A occurring.
• $P(B)$ is the probability of event B occurring.
• $P(A \cap B)$ is the probability that both events A and B occur.

This formula accounts for the overlap between A and B by subtracting $P(A \cap B)$, ensuring that the probability is not counted twice.

If you have specific values for $P(A)$, $P(B)$, and $P(A \cap B)$, I can help you calculate $P(A \cup B)$.