A number greater than 32 would require a minimum of how may bits in binary representation

To determine the minimum number of bits required to represent a number greater than 32 in binary, we need to understand how binary numbers work.

Binary numbers are base 2, meaning each digit represents a power of 2. The rightmost digit represents 2^0 (1), the next digit to the left represents 2^1 (2), then 2^2 (4), 2^3 (8), and so on.

To represent the number 32 in binary, we would need 6 bits. The binary representation of 32 is 100000. As you can see, there are 6 digits or bits in this binary number.

However, the question asks for a number greater than 32. This means we need at least one more bit to represent such a number. Therefore, a number greater than 32 would require a minimum of 7 bits in binary representation.