Suggest which out of lithium fluoride, beryllium oxide and nitrogen monoxide will be the most ionic in the properties.

To determine which compound will be the most ionic, we need to look at the difference in electronegativity between the atoms in each compound. The greater the difference in electronegativity, the more ionic the bond is.

1. Lithium Fluoride (LiF): Lithium (Li) has an electronegativity of 1.0, and Fluorine (F) has an electronegativity of 3.98. The difference is 2.98.

2. Beryllium Oxide (BeO): Beryllium (Be) has an electronegativity of 1.57, and Oxygen (O) has an electronegativity of 3.44. The difference is 1.87.

3. Nitrogen Monoxide (NO): Nitrogen (N) has an electronegativity of 3.04, and Oxygen (O) has an electronegativity of 3.44. The difference is 0.4.

From these calculations, we can see that Lithium Fluoride (LiF) has the greatest difference in electronegativity, and therefore, it will be the most ionic in properties.