The average of 9z numbers is 12z. If 4z-2 is subtracted from each, then the new average is?Options10z - 28z - 212z + 28z + 2
Question
The average of 9z numbers is 12z. If 4z-2 is subtracted from each, then the new average is?
Options:
- 10z
- 28z
- 2
- 12z + 28z
- 2
Solution
The average of a set of numbers is calculated by summing all the numbers and dividing by the count of numbers. In this case, the average of 9z numbers is 12z, which means the total sum of the numbers is 9z * 12z = 108z^2.
If 4z-2 is subtracted from each number, the total amount subtracted from the sum is (4z-2) * 9z = 36z^2 - 18z.
So, the new sum of the numbers is 108z^2 - (36z^2 - 18z) = 72z^2 + 18z.
The new average is this sum divided by the count of numbers, which is 9z. So, the new average is (72z^2 + 18z) / 9z = 8z + 2.
So, the correct option is 8z + 2.
Similar Questions
The average of 10 numbers is 7. If each number is multiplied by 12, then the average of the new set of numbers will be?Options7828419
The average of 9 numbers is 14. If each number is increased by 4, the new average will be
The average of 9 numbers is 30.If the average of first '5' numbers is 25 and that of the last '3' number is 35.Then the 6th number?30405060
The average of 23 numbers is 77. If each number is divided by 4, then the average of new set of numbers is:
The average of n numbers is x. when 36 is subtracted from two of the numbers, the new average becomes (x-8).The value of n is:9465
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.