A line passes through the points (–16,13) and (15,–18). Write its equation in slope-intercept form.

Sure, here are the steps to find the equation of the line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept.

Step 1: Find the slope (m) of the line using the formula m = (y2 - y1) / (x2 - x1). Here, (x1, y1) = (-16, 13) and (x2, y2) = (15, -18).

m = (-18 - 13) / (15 - (-16)) = -31 / 31 = -1

Step 2: Substitute the slope (m = -1) and one of the points into the equation y = mx + b to solve for b. Let's use the point (-16, 13).

13 = -1 * -16 + b 13 = 16 + b Subtract 16 from both sides to solve for b: b = 13 - 16 = -3

Step 3: Substitute m = -1 and b = -3 into the equation y = mx + b to get the equation of the line:

y = -1x - 3

So, the equation of the line that passes through the points (-16,13) and (15,-18) in slope-intercept form is y = -x - 3.