The rate constant of a first order reaction is 4×10−3sec−1 .At a reactant concentration of 0.02 M, the rate of reaction would be:
Question
The rate constant of a first order reaction is 4×10^{-3} sec^{-1}. At a reactant concentration of 0.02 M, the rate of reaction would be:
Solution
The rate of a first order reaction can be calculated using the formula:
Rate = k[A]
where:
- Rate is the rate of reaction,
- k is the rate constant, and
- [A] is the concentration of the reactant.
Given in the problem, we have:
- k = 4×10−3 sec−1, and
- [A] = 0.02 M.
Substituting these values into the formula, we get:
Rate = (4×10−3 sec−1)(0.02 M) = 8×10−5 M/sec.
So, the rate of reaction would be 8×10−5 M/sec.
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