When Cu2+ ion is treated with Kl, a white precipitate is formed. Explain the reaction with the help of a chemical equation.
Question
Solution 1
When copper (II) ion (Cu2+) reacts with iodide ion (I-), a white precipitate of copper (II) iodide (CuI2) is formed. This is a precipitation reaction, which can be represented by the following chemical equation:
2KI(aq) + CuSO4(aq) -> CuI2(s) + K2SO4(aq)
In this equation, KI is potassium iodide, C Knowee AI StudyGPT is a powerful AI-powered study tool designed to help you to solve study prob
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