Find the number of odd days in first 1500 years?      a.0         b.1     c.2     d.3

To find the number of odd days in the first 1500 years, we need to consider the concept of leap years.

Step 1: Determine the number of leap years in the given time period.

A leap year occurs every 4 years, except for years that are divisible by 100 but not divisible by 400.

To find the number of leap years in 1500 years, we divide 1500 by 4:

1500 ÷ 4 = 375 leap years.

However, we need to subtract the number of years that are divisible by 100 but not divisible by 400.

To find these years, we divide 1500 by 100:

1500 ÷ 100 = 15 years.

But we also need to divide 1500 by 400:

1500 ÷ 400 = 3 years.

So, the number of years that are divisible by 100 but not divisible by 400 is 15 - 3 = 12 years.

Therefore, the number of leap years in the first 1500 years is 375 - 12 = 363 leap years.

Step 2: Calculate the number of normal years.

To find the number of normal years, we subtract the number of leap years from the total number of years:

1500 - 363 = 1137 normal years.

Step 3: Calculate the number of odd days.

In a normal year, there are 365 days, which is equivalent to 1 odd day.

So, the number of odd days in the normal years is 1137.

In a leap year, there are 366 days, which is equivalent to 2 odd days.

So, the number of odd days in the leap years is 363 x 2 = 726.

Step 4: Add the number of odd days in normal years and leap years.

1137 + 726 = 1863 odd days.

Step 5: Reduce the number of odd days to a smaller value.

Since 7 days make a week, we divide 1863 by 7:

1863 ÷ 7 = 266 remainder 1.

Therefore, the number of odd days in the first 1500 years is 1.

So, the correct answer is b. 1.