Write a class to sort the given set of integers in descending order. Include a try block tolocate the array index out of bounds exception and catch it.

Here's a Python class that sorts a given set of integers in descending order, and includes error handling to catch any potential index out of bounds exceptions:

class DescendingSorter:
    def __init__(self, integer_array):
        self.integer_array = integer_array

    def sort_descending(self):
        try:
            # Attempt to access an index (this is just an example, so we won't actually be out of bounds)
            print(self.integer_array[len(self.integer_array)])
        except IndexError as e:
            print("Caught an IndexError: ", e)
        
        # Sort the array in descending order
        sorted_array = sorted(self.integer_array, reverse=True)
        return sorted_array

# Example usage
if __name__ == "__main__":
    integers = [5, 2, 9, 1, 5, 6]
    sorter = DescendingSorter(integers)
    result = sorter.sort_descending()
    print("Sorted Integers in Descending Order:", result)

Explanation:

1. Class Definition: The class DescendingSorter is defined with an __init__ method to initialize the input array.
2. Sorting Method: The sort_descending method sorts the integers in descending order and attempts to access an out-of-bounds index to demonstrate error handling.
3. Error Handling: A try-except block is used to catch an IndexError, printing a message if it occurs.
4. Example Usage: An example shows how to create an instance of the class and call the sorting method.

Final Result

When run, the program will print the sorted integers in descending order along with handling for any out of bounds access, though in this example, it specifically demonstrates the error handling capability.