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Drag the labels to the correct locations on the image. Not all labels will be used.Consider function h.What is the range of function h?∞𝑦-4-2𝑥2-1-∞

Question

Drag the labels to the correct locations on the image. Not all labels will be used.

Consider function h. What is the range of function h?
y42x21 ∞ \, y \, -4 \, -2 \, x^2 \, -1 \, -∞

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Solution

To determine the range of the function h h , we need to understand the possible values that h(x) h(x) can take. Here are the steps to find the range:

  1. Identify the function h(x) h(x) : The problem does not provide the explicit form of h(x) h(x) , so we will assume it is a general function. If you have the specific form of h(x) h(x) , please provide it.

  2. Analyze the function: If h(x) h(x) is a common function like a polynomial, rational function, trigonometric function, etc., we can analyze its behavior to determine the range.

  3. Consider the domain: The range of a function depends on its domain. Ensure you know the domain of h(x) h(x) .

  4. Evaluate the function: Determine the minimum and maximum values (if they exist) that h(x) h(x) can take. This can involve finding critical points, asymptotes, or limits.

Since the problem mentions labels like \infty , y y , 4 -4 , 2 -2 , x x , 2 2 , 1 -1 , and -\infty , we can infer that these might be potential values or boundaries for the range.

Example Analysis (Assuming a Quadratic Function)

Let's assume h(x)=x24 h(x) = x^2 - 4 as an example:

  1. Identify the function: h(x)=x24 h(x) = x^2 - 4 .

  2. Analyze the function: This is a quadratic function that opens upwards (since the coefficient of x2 x^2 is positive).

  3. Consider the domain: The domain of h(x) h(x) is all real numbers (<x< -\infty < x < \infty ).

  4. Evaluate the function:

    • The vertex of the parabola y=x24 y = x^2 - 4 is at (0,4) (0, -4) .
    • As x x approaches \infty or -\infty , h(x) h(x) approaches \infty .

Therefore, the minimum value of h(x) h(x) is 4 -4 , and there is no maximum value (it goes to \infty ).

Range

The range of h(x)=x24 h(x) = x^2 - 4 is [4,) [-4, \infty) .

Label Placement

Based on the example function h(x)=x24 h(x) = x^2 - 4 :

  • The minimum value is 4 -4 .
  • The function increases without bound, so the range extends to \infty .

Thus, the correct labels for the range of h h would be 4 -4 and \infty .

If you provide the specific form of h(x) h(x) , I can give a more precise answer.

This problem has been solved

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